¿Ã·¹Æ÷Æ® : ´ëÇз¹Æ÷Æ®, Á·º¸, ½ÇÇè°úÁ¦, ½Ç½ÀÀÏÁö, ±â¾÷ºÐ¼®, »ç¾÷°èȹ¼­, Çо÷°èȹ¼­, ÀÚ±â¼Ò°³¼­, ¸éÁ¢, ¹æ¼ÛÅë½Å´ëÇÐ, ½ÃÇè ÀÚ·á½Ç
¿Ã·¹Æ÷Æ® : ´ëÇз¹Æ÷Æ®, Á·º¸, ½ÇÇè°úÁ¦, ½Ç½ÀÀÏÁö, ±â¾÷ºÐ¼®, »ç¾÷°èȹ¼­, Çо÷°èȹ¼­, ÀÚ±â¼Ò°³¼­, ¸éÁ¢, ¹æ¼ÛÅë½Å´ëÇÐ, ½ÃÇè ÀÚ·á½Ç
·Î±×ÀΠ ȸ¿ø°¡ÀÔ

ÆÄÆ®³Ê½º

ÀÚ·áµî·Ï
 

Àå¹Ù±¸´Ï

´Ù½Ã¹Þ±â

ÄÚÀÎÃæÀü

¢¸

  • º» ¹®¼­ÀÇ
    ¹Ì¸®º¸±â´Â
    Pg ±îÁö¸¸
    °¡´ÉÇÕ´Ï´Ù.
¢º
Ŭ¸¯ : Å©°Ôº¸±â


  • º» ¹®¼­ÀÇ
    (Å« À̹ÌÁö)
    ¹Ì¸®º¸±â´Â
    Page ±îÁö¸¸
    °¡´ÉÇÕ´Ï´Ù.
  ´õºíŬ¸¯ : ´Ý±â
X ´Ý±â
Á¿ìÀ̵¿ : µå·¡±×

¸Æ±×·ÎÈú ±â°è¿ä¼Ò¼³°è 9ÆÇ ¼Ö·ç¼Ç (shigleys mechanical engineering design 9th , budynas , nisbett , (mcgraw hill)) (±¸¸ÅÀÚ ÆÇ¸ÅÁßÁö)

ÀÎ ¼â
¹Ù·Î°¡±â
Áñ°Üã±â Űº¸µå¸¦ ´­·¯ÁÖ¼¼¿ä
( Ctrl + D )
¸µÅ©º¹»ç ¸µÅ©ÁÖ¼Ò°¡ º¹»ç µÇ¾ú½À´Ï´Ù.
¿øÇÏ´Â °÷¿¡ ºÙÇô³Ö±â Çϼ¼¿ä
( Ctrl + V )
¿ÜºÎ°øÀ¯
ÆÄÀÏ    [Size : 0 Kbyte ]
ºÐ·®   Page


īƮ
´Ù¿î¹Þ±â
īī¿À ID·Î
´Ù¿î ¹Þ±â
±¸±Û ID·Î
´Ù¿î ¹Þ±â
ÆäÀ̽ººÏ ID·Î
´Ù¿î ¹Þ±â
µÚ·Î

ÀÚ·á¼³¸í
[ÆÇ¸ÅÁßÁö] ±¸¸Åȸ¿ø¿äû ÆÇ¸ÅÁßÁö(»çÀ¯) : 5Àå ¼Ö·ç¼ÇÀÌ ¾È¿­¸®³×¿ä -------> [¼Ö·ç¼Ç] ±â°è¿ä¼Ò¼³°è 9ÆÇ(shigleys mechanical engineering design 9th,budynas, nisbett, mcgraw hill) ÀÔ´Ï´Ù. éÅÍ 1ºÎÅÍ 20±îÁö ÀÖ½À´Ï´Ù ±×·± éÅÍ 18, 19´Â ¾ø½À´Ï´Ù. ÀÌÁ¡ Âü°íÇØÁÖ½Ã±æ ¹Ù¶ø´Ï´Ù..^^ °øºÎ ÇÒ ¶§ Á¤¸» µµ¿òÀÌ ¸¹ÀÌ ‰ç´ø ÀÚ·á ÀÔ´Ï´Ù. ¼ö¾÷À» µû¶ó°¡¸é¼­ ÀÌÇØ ¾È°¡´Â ºÎºÐÀÌ ÀÖÀ¸¸é üũ ÇÏ´Â ¹æ½Äµµ ±¦ÂúÀ¸¸ç, ¶Ç ¼ö¾÷ÀÌ µéÀºÁö ¿À·¡µÇ¾î ´Ù½Ã °øºÎÇϰíÀÚ ÇÒ¶§ µµ¿òÀÌ µÇ´Â ¼Ö·ç¼ÇÀÔ´Ï´Ù..^^ ±×¸®°í ½ÃÇè±â°£¿¡´Â Á¤¸» ¾ø¾î¼­´Â ¾ÈµÉ ÀÚ·áÀ̱⵵ Çϱ¸¿ä..^^
¸ñÂ÷/Â÷·Ê
éÅÍ 1ÀÇ ÇѺκÐÀ» ¹ßÃé ÇÑ °ÍÀÔ´Ï´Ù.
Chapter 1
Problems 1-1 through 1-6 are for student research. No standard solutions are provided.
1-7 From Fig. 1-2, cost of grinding to  0.0005 in is 270%. Cost of turning to  0.003 in is 60%.
Relative cost of grinding vs. turning = 270/60 = 4.5 times Ans.
______________________________________________________________________________
1-8 CA = CB,
10 + 0.8 P = 60 + 0.8 P  0.005 P 2
P 2 = 50/0.005  P = 100 parts Ans.
______________________________________________________________________________
1-9 Max. load = 1.10 P
Min. area = (0.95)2A
Min. strength = 0.85 S
To offset the absolute uncertainties, the design factor, from Eq. (1-1) should be
21.101.43.0.850.95dnA
______________________________________________________________________________
1-10 (a) X1 + X2:
121122121212error .xxXeXeexxXXeeAns
(b) X1  X2:
121122121212 .xxXeXeexxXXeeAns
(c) X1 X2:
12112212121221121212211212 .xxXeXeexxXXXeXeeeeeXeXeXXAnsXX
Chapter 1 Solutions
ÃßõÀÚ·á



ÀúÀÛ±ÇÁ¤º¸
*À§ Á¤º¸ ¹× °Ô½Ã¹° ³»¿ëÀÇ Áø½Ç¼º¿¡ ´ëÇÏ¿© ȸ»ç´Â º¸ÁõÇÏÁö ¾Æ´ÏÇϸç, ÇØ´ç Á¤º¸ ¹× °Ô½Ã¹° ÀúÀ۱ǰú ±âŸ ¹ýÀû Ã¥ÀÓÀº ÀÚ·á µî·ÏÀÚ¿¡°Ô ÀÖ½À´Ï´Ù. À§ Á¤º¸ ¹× °Ô½Ã¹° ³»¿ëÀÇ ºÒ¹ýÀû ÀÌ¿ë, ¹«´Ü ÀüÀ硤¹èÆ÷´Â ±ÝÁöµÇ¾î ÀÖ½À´Ï´Ù. ÀúÀÛ±ÇÄ§ÇØ, ¸í¿¹ÈÑ¼Õ µî ºÐÀï¿ä¼Ò ¹ß°ß½Ã °í°´¼¾ÅÍÀÇ ÀúÀÛ±ÇÄ§ÇØ½Å°í ¸¦ ÀÌ¿ëÇØ Áֽñ⠹ٶø´Ï´Ù.
📝 Regist Info
I D : ********
Date :
FileNo : 15112705

Cart