[일반화학] 대학화학의 기초 12판 솔루션 (Foundations of College Chemistry Alternate 12ed) (구매자 판매중지)

UNITS, PHYSICAL QUANTITIES AND VECTORS

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1.1.

IDENTIFY: Convert units from mi to km and from km to ft. SET UP: 1 in. = 2.54 cm , 1 km = 1000 m , 12 in. = 1 ft , 1 mi = 5280 ft . ? 5280 ft ?? 12 in. ?? 2.54 cm ?? 1 m ?? 1 km ? EXECUTE: (a) 1.00 mi = (1.00 mi) ? ?? ?? ?? 2 ?? 3 ? = 1.61 km ? 1 mi ?? 1 ft ?? 1 in. ?? 10 cm ?? 10 m ?

1.2.

? 103 m ?? 102 cm ? ? 1 in. ?? 1 ft ? 3 (b) 1.00 km = (1.00 km) ? ?? ?? ?? ? = 3.28 × 10 ft 1 km ?? 1 m ? ? 2.54 cm ?? 12 in. ? ? EVALUATE: A mile is a greater distance than a kilometer. There are 5280 ft in a mile but only 3280 ft in a km. IDENTIFY: Convert volume units from L to in.3 . SET UP: 1 L = 1000 cm3 . 1 in. = 2.54 cm
? 1000 cm3 ? ? 1 in. ? 3 0.473 L × ? ?×? ? = 28.9 in. . ? 1 L ? ? 2.54 cm ? EVALUATE: 1 in.3 is greater than 1 cm3 , so the volume in in.3 is a smaller number than the volume in cm3 , which is 473 cm3 . IDENTIFY: We know the speed of light in m/s. t = d / v . Convert 1.00 ft to m and t from s to ns. SET UP: The s…(생략)